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6 points
by
waterhouse
5186 days ago |
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[_] = (fn (x) (x)), not (fn (x) x).
[idfn _] = (fn (x) x). ([idfn _] 1) -> 1.
1 point
by
d0m
5186 days ago |
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Oh my ... thank you. That explains a lot of things :p
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